The reaction \( 2 \, NO_2Cl(g) \rightarrow 2 \, NO_2(g) + Cl_2(g) \) takes place in two steps as
\text{(i) } \( NO_2Cl(g) \rightarrow NO_2(g) + Cl(g) \)
\text{(ii) } \( NO_2Cl(g) + Cl(g) \rightarrow NO_2(g) + Cl_2(g) \)
\text{Identify the reaction intermediate.