Each atom of an iron bar $(5\, cm \times 1\, cm \times 1\, cm )$ has a magnetic moment $1.8 \times 10^{-23}\, Am ^{2}$. Knowing that the density of iron is $7.78 \times 10^{3}\, kg\, m ^{-3}$, atomic weight is $56$ and Avogadro's number is $6.02 \times 10^{23}$ the magnetic moment of bar in the state of magnetic saturation will be