Consider the following cell at 298 K.
M(s) $|$ M$^{2+$ (x M) $||$ Zn$^{2+}$ (y M) $|$ Zn(s)}
The cell reaction reached the equilibrium state. The value of $\log \left( \frac{[M^{2+}]}{[Zn^{2+}]} \right)$ is 53.33.
What is the value of $E^\Theta_{\text{M^{2+}/\text{M}}$ (in volts)?}
Given:
\[
E^\Theta_{\text{Zn}^{2+}/\text{Zn}} = -0.76\,\text{V}, \quad \frac{2.303\,RT}{F} = 0.06\,\text{V}
\]