y= e2x (a+bx)....(1)
Differentiating both sides with respect to x, we get:
y'= 2e2x (a+bx)+e2x .b
⇒y'= e2x (2a+2bx+b)...(2)
Multiplying equation(1) with equation (2) and then subtracting it from equation (2),we get:
y'-2y=e2x (2a+2bx+b)-e2x (2a+2bx)
\(\Rightarrow\) y'-2=be2x...(3)
Differentiating both sides with respect to x, we get:
y''k-2y'=2be2x....(4)
Dividing equation(4)by equation(3),we get:
\(\frac{y''-2y''}{y'-2y}=2\)
\(\Rightarrow\) y''-2y'=2y'-4y
\(\Rightarrow\) y''-4y'+4y=0
This is the required differential equation of the given curve.
Let $ y(x) $ be the solution of the differential equation $$ x^2 \frac{dy}{dx} + xy = x^2 + y^2, \quad x > \frac{1}{e}, $$ satisfying $ y(1) = 0 $. Then the value of $ 2 \cdot \frac{(y(e))^2}{y(e^2)} $ is ________.
A relation between involved variables, which satisfy the given differential equation is called its solution. The solution which contains as many arbitrary constants as the order of the differential equation is called the general solution and the solution free from arbitrary constants is called particular solution.
Read More: Formation of a Differential Equation