Question:

X reacts with NaOH (aqueous solution) to form Y and $H_2$. Aqueous solution of Y is heated to 323- 333 K and on passing $ {CO_2}$ into it, $ {Na_2CO_3}$ and Z were formed. When Z is heated to $1200^{\circ}C , { Al_2O_3}$ is formed. X, Y and Z respectively are

Updated On: Jul 7, 2022
  • $\ce{Al, AlCl_3, NaAlO_2}$
  • $\ce{Zn, Na_2ZnO_2, Al(OH)_3}$
  • $\ce{Al, Al(OH)_3, AlCl_3}$
  • $\ce{Al, NaAlO_2, Al(OH)_3}$
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The Correct Option is D

Solution and Explanation

Answer (d) $ {Al, NaAlO_2, Al(OH)_3}$
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Notes on p -Block Elements

Concepts Used:

P-Block Elements

  • P block elements are those in which the last electron enters any of the three p-orbitals of their respective shells. Since a p-subshell has three degenerate p-orbitals each of which can accommodate two electrons, therefore in all there are six groups of p-block elements.
  • P block elements are shiny and usually a good conductor of electricity and heat as they have a tendency to lose an electron. You will find some amazing properties of elements in a P-block element like gallium. It’s a metal that can melt in the palm of your hand. Silicon is also one of the most important metalloids of the p-block group as it is an important component of glass.

P block elements consist of: