Answer:
Biphenyl (C6H5–C6H5)
Explanation:
When chlorobenzene is treated with sodium metal in dry ether, it undergoes the **Wurtz–Fittig reaction**.
2 C6H5Cl + 2 Na ⟶ C6H5–C6H5 + 2 NaCl
The product formed is biphenyl.
Match the LIST-I with LIST-II: 
Choose the correct answer from the options given below:
CH$_3$–Br $\xrightarrow{\text{CH$_3$OH/Nu}}$ CH$_3$OH
Correct order of rate of this reaction for given nucleophile:
