Question:

Write the reactions involved in the following:
(i) Reimer-Tiemann reaction
(ii) Kolbe’s reaction

Updated On: Feb 17, 2025
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Solution and Explanation

(i) Reimer-Tiemann Reaction: The Reimer-Tiemann reaction involves the introduction of a formyl group (–CHO) to the aromatic ring using chloroform (\( \text{CHCl}_3 \)) and sodium hydroxide (\( \text{NaOH} \)): \[ \text{C}_6\text{H}_5\text{OH} + \text{CHCl}_3 + \text{NaOH} \rightarrow \text{C}_6\text{H}_4\text{CHO} + \text{NaCl} + \text{H}_2\text{O} \] (ii) Kolbe’s Reaction: This reaction involves the carboxylation of sodium phenoxide with carbon dioxide under high pressure, yielding salicylic acid: \[ \text{C}_6\text{H}_5\text{O}Na + \text{CO}_2 \xrightarrow{\text{High Pressure}} \text{C}_6\text{H}_4\text{COOH} + \text{NaOH} \]
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