Answer:
Na3AlF6 (Sodium hexafluoroaluminate)
Explanation:
Cryolite is a double fluoride of sodium and aluminium, having the chemical formula Na3AlF6.
It is used as a solvent for alumina (Al2O3) in the Hall–Héroult process for the extraction of aluminium, as it lowers the melting point and increases conductivity of the electrolyte.
On charging the lead storage battery, the oxidation state of lead changes from $\mathrm{x}_{1}$ to $\mathrm{y}_{1}$ at the anode and from $\mathrm{x}_{2}$ to $\mathrm{y}_{2}$ at the cathode. The values of $\mathrm{x}_{1}, \mathrm{y}_{1}, \mathrm{x}_{2}, \mathrm{y}_{2}$ are respectively:
1 Faraday electricity was passed through Cu$^{2+}$ (1.5 M, 1 L)/Cu and 0.1 Faraday was passed through Ag$^+$ (0.2 M, 1 L) electrolytic cells. After this, the two cells were connected as shown below to make an electrochemical cell. The emf of the cell thus formed at 298 K is:
Given: $ E^\circ_{\text{Cu}^{2+}/\text{Cu}} = 0.34 \, \text{V} $ $ E^\circ_{\text{Ag}^+/ \text{Ag}} = 0.8 \, \text{V} $ $ \frac{2.303RT}{F} = 0.06 \, \text{V} $