Step 1: Understanding the Concept:
NOR and NAND gates are known as universal logic gates. They are combinations of basic gates (OR, AND) with a NOT gate.
- NOR = NOT + OR. It gives a high output (1) only when all its inputs are low (0).
- NAND = NOT + AND. It gives a low output (0) only when all its inputs are high (1).
Step 2: NOR Gate Details:
The NOR gate is an OR gate followed by a NOT gate.
Boolean Expression:
The expression for an OR gate with inputs A and B is \(A+B\). The NOR gate inverts this output. Therefore, the Boolean expression is:
\[ Y = \overline{A+B} \]
This is read as "Y equals NOT (A OR B)".
Truth Table:
| Inputs | OR Output | NOR Output | |
|---|---|---|---|
| A | B | A + B | Y = \(\overline{A + B}\) |
| 0 | 0 | 0 | 1 |
| 0 | 1 | 1 | 0 |
| 1 | 0 | 1 | 0 |
| 1 | 1 | 1 | 0 |
Step 3: NAND Gate Details:
The NAND gate is an AND gate followed by a NOT gate.
Boolean Expression:
The expression for an AND gate with inputs A and B is \(A \cdot B\). The NAND gate inverts this output. Therefore, the Boolean expression is:
\[ Y = \overline{A \cdot B} \]
This is read as "Y equals NOT (A AND B)".
Truth Table:
| Inputs | AND Output | NAND Output | |
|---|---|---|---|
| A | B | A \(\cdot\) B | Y = \(\overline{A \cdot B}\) |
| 0 | 0 | 0 | 1 |
| 0 | 1 | 0 | 1 |
| 1 | 0 | 0 | 1 |
| 1 | 1 | 1 | 0 |
Step 4: Final Answer:
The Boolean expressions and truth tables for NOR and NAND gates are provided as detailed above.
Match the LIST-I with LIST-II
| LIST-I (Logic Gates) | LIST-II (Expressions) | ||
|---|---|---|---|
| A. | EX-OR | I. | \( A\bar{B} + \bar{A}B \) |
| B. | NAND | II. | \( A + B \) |
| C. | OR | III. | \( AB \) |
| D. | EX-NOR | IV. | \( \bar{A}\bar{B} + AB \) |
Choose the correct answer from the options given below:
Match List-I with List-II:
| List-I (Counters) | List-II (Delay/Number of States) |
|---|---|
| (A) n-bit ring counter | (I) Number of states is \( 2^n \) |
| (B) MOD-\(2^n\) asynchronous counter | (II) Fastest counter |
| (C) n-bit Johnson counter | (III) Number of used states is \( n \) |
| (D) Synchronous counter | (IV) Number of used states is \( 2n \) |
Choose the correct answer from the options given below:
A MOD 2 and a MOD 5 up-counter when cascaded together results in a MOD ______ counter.