Question:

Why is partial roasting of sulphide ore done in metallurgy of copper?

Updated On: Jul 7, 2022
  • Auto-reduction of $Cu_2O$ formed is carried out by remaining $Cu_2S$ in the reaction
  • $Cu$ is separated out by partial reduction due to sedimentation
  • Due to difference in gravity $Cu_2O$ and $Cu_2S$ are separated
  • Complete roasting cannot be done in one step hence partial roasting is done
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The Correct Option is A

Solution and Explanation

Partial roasting of sulphide ore forms some oxide. This oxide then reduces the remaining sulphide ore into metal. $2Cu_2S + 3O_2 \to 2Cu_2O + 2SO_2$ $2Cu_2O + Cu_2S \to 6Cu + SO_2$ This process is called autoreduction.
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Concepts Used:

General Principles and Processes of Isolation of Elements

What are Ores and Minerals? 

Minerals are the naturally occurring, homogeneous inorganic solid substances. They are having a definite chemical composition and crystalline structure, hardness and color. For example, copper pyrite, calamine, etc.

Impurities in an ore are called gauge. The removal of a gauge from the ore is called concentration ore. 

Several steps are involved in the extraction of pure metal from ores. Major steps are as follows –

  • Concentration of the ore
  • Isolation of the metal from its concentrated ore
  • Purification of the metal