Question:

Which one of the following equations suggests that $O _{2}$ released during photosynthesis comes from water?

Updated On: Jul 7, 2022
  • $6CO_{2}\,^{18}+12H_{2} \to 6O_{2}\,^{18} +C_{6}H_{12}O_{6} + 6H_{2}O\,^{18}$
  • $6CO_{2}+12H_{2} O\,^{18} \to 6O_{2} +C_{6}H_{12}O_{6} + 6H_{2}O\,^{18}$
  • $6CO_{2}\,^{18}+12H_{2} \to 6O_{2}\,^{18} +C_{6}H_{12}O_{6} + 6H_{2}O$
  • $6CO_{2}+12H_{2} O\,^{18} \to 6O_{2}\,^{18} +C_{6}H_{12}O_{6} + 6H_{2}O$
Hide Solution
collegedunia
Verified By Collegedunia

The Correct Option is D

Solution and Explanation

Ruben and Kamen $(1941)$, while working on Chlorella (unicellular green alga) found that oxygen liberated during photosynthesis comes from water. (i) When normal $H_{2}O$ and radioactive $CO_{2}$ (i.e., $CO^{18}\,_{2}$) were used, normal $O_{2}$ is evolved. $nCO_{2}^{18} + nH_{2}O$$ {->[{\text{Light}}][{\text{Chlorophyll}}]}$$(CH_{2}O^{18})_n + nO_{2} ? (ii) When normal $CO_{2}$ and radioactive $H_{2}O$ (i.e., $H_{2}O^{ 18}$) were used, radioactive $O_{2}$ (i.e., $O_{2}^{8}$ ) is evolved. $nCO_{2} +nH_{2}O^{18} \to (CH_{2}O)_n+O^{18}_{2}?
Was this answer helpful?
0
0

Concepts Used:

Photosynthesis in Higher Plants

Processes Of Photosynthesis in Higher Plants:

Photosynthesis in higher plants involves the following processes:

  • Light Reaction
  • Dark Reaction

Light Reaction:

  • This phenomenon occurs in the presence of light.
  • The pigment absorbs light and produces energy in the form of ATP.
  • The process involves- absorption of light, water splitting, the release of oxygen, and formation of ATP and NADPH.

Dark Reaction:

This process occurs in the absence of light in the stroma of the chloroplasts. The following cycles are involved in the process:

  1. Calvin Cycle (C3 Cycle)
  2. C4 Cycle (Hatch and Slack Pathway)