Question:

Which one has the lowest boiling point?

Updated On: Apr 27, 2024
  • $NH_3$
  • $PH_3$
  • $AsCI_3$
  • $SbH_3$
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The Correct Option is B

Solution and Explanation

In the hydrides of group number five, the boiling
points changes as
$_{238.5K}^{ \, \, NH_3 \, \, \, >} \, _{185.5 K}^{ \, \, PH_3} \, _{\, \, \, \, 254.6 K}^{ < \, \, AsH_3} \, _{ \, \, \, \, 254.6 K}^{< \, \, SbH_3} \, _{ \, \, \, \, \, \, 290 K}^{< \, \, \, BiH_3}$
$\therefore \, $ Generally mass increases then boiling point increases.
The higher boiling point of $NH_3$ is due to excessive
hydrogen bonding, so $PH_3$ have lowest boiling point
among hydrides of group number 15, i.e. nitrogen
family.
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  • P block elements are those in which the last electron enters any of the three p-orbitals of their respective shells. Since a p-subshell has three degenerate p-orbitals each of which can accommodate two electrons, therefore in all there are six groups of p-block elements.
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