Question:

Which of the reactions is used in the conversion of a ketone into hydrocarbon?

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Remember: - {Clemmensen reduction} → Acidic conditions (Zn-Hg/HCl) - {Wolff-Kishner reduction} → Basic conditions (Hydrazine + KOH) Both convert carbonyl groups into hydrocarbons.
  • Reimer-Tiemann reaction
  • Wolff-Kishner reduction
  • Aldol condensation
  • Stephen reaction
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The Correct Option is B

Solution and Explanation

Concept: To convert a ketone into a hydrocarbon, the carbonyl group (\( C=O \)) must be completely removed and replaced by hydrogen atoms. This type of transformation is called
reduction of carbonyl compounds to alkanes. Two major reactions do this:
  • Clemmensen reduction (acidic medium)
  • Wolff-Kishner reduction (basic medium)
Among the given options, only one performs complete reduction of a ketone to a hydrocarbon.
Step 1: Understanding each option.
(A) Reimer-Tiemann reaction: Used for formylation of phenols to give salicylaldehyde. It does
not reduce ketones.
(B) Wolff-Kishner reduction: This reaction converts aldehydes or ketones into hydrocarbons using hydrazine (\( NH_2NH_2 \)) and strong base at high temperature: \[ R{-}CO{-}R' \xrightarrow[\text{KOH, heat}]{NH_2NH_2} R{-}CH_2{-}R' \] Thus, the carbonyl group is completely removed.
(C) Aldol condensation: Forms \( \beta \)-hydroxy aldehydes/ketones or \( \alpha,\beta \)-unsaturated compounds. It is a
C–C bond forming reaction, not a reduction.
(D) Stephen reaction: Used to convert nitriles into aldehydes. It is unrelated to ketone reduction.
Step 2: Final selection. Only the Wolff-Kishner reduction converts a ketone into a hydrocarbon. \[ \therefore \text{Correct answer = (B) Wolff-Kishner reduction} \]
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