Question:
Which of the following will be able to show geometrical isomerism ?
Which of the following will be able to show geometrical isomerism ?
Updated On: Apr 2, 2024
- $MA_3B$ - Square planar
- $MA_2B_2$, - Tetrahedral
- $MABCD$ - Square planar
- $MABCD$ - Tetrahedral
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The Correct Option is C
Solution and Explanation
Tetrahedral complexes do not show geometrical isomerism because relative position of unidentate ligands attached to central metal atom are same with respect to each other.
So, options (b) and (d) are not correct.
Square planar complex $M A_{3} B$ (option (a) do not show geometrical isomerism because the possible spatial arrangement are equivalent. Squar planar complex MABCD type form three isomers (cis-trans isomerism), two of these are cis and one is trans.
So, options (b) and (d) are not correct.
Square planar complex $M A_{3} B$ (option (a) do not show geometrical isomerism because the possible spatial arrangement are equivalent. Squar planar complex MABCD type form three isomers (cis-trans isomerism), two of these are cis and one is trans.
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Concepts Used:
Coordination Compounds
A coordination compound holds a central metal atom or ion surrounded by various oppositely charged ions or neutral molecules. These molecules or ions are re-bonded to the metal atom or ion by a coordinate bond.
Coordination entity:
A coordination entity composes of a central metal atom or ion bonded to a fixed number of ions or molecules.
Ligands:
A molecule, ion, or group which is bonded to the metal atom or ion in a complex or coordination compound by a coordinate bond is commonly called a ligand. It may be either neutral, positively, or negatively charged.