1. d9 (high spin):
2. d6 (low spin):
3. d4 (low spin):
4. d7 (high spin):
Comparison:
Conclusion:
The correct answer is Option 4.
This document analyzes the number of unpaired electrons in different d-electron configurations within an octahedral field, considering both high-spin and low-spin cases.
In an octahedral field, the d orbitals split into $t_{2g}$ (lower energy) and $e_g$ (higher energy) sets.
d9 configuration: $t_{2g}^6 e_g^3$
Number of unpaired electrons: 1
d6 configuration (low spin): $t_{2g}^6 e_g^0$
Number of unpaired electrons: 0
d4 configuration (low spin): $t_{2g}^4 e_g^0$
Number of unpaired electrons: 2
d7 configuration (high spin): $t_{2g}^5 e_g^2$
Number of unpaired electrons: 3
A summary of the number of unpaired electrons for each configuration:
The d7 (high spin) configuration has the maximum number of unpaired electrons (3).
Therefore, Option 4 is the correct answer.
The structure of the major product formed in the following reaction is:
The steam volatile compounds among the following are:
The structure of the major product formed in the following reaction is: