Silicon exhibits 4 coordination number in its compounds
Bond energy of $F_2$ is less than $Cl_2$
Mn(lll) oxidation state is more stable than Mn(ll) in aqueous state
Elements of $15^{th}$ group shows only +3 and +5 oxidation states
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The Correct Option isB
Solution and Explanation
Bond energy of $F_2$ is less than $CI_2$ because in $F_2$ molecule electron-electron repulsion of 2p-orbital of two fluorine atom is maximum in comparison to the repulsion of 3p-orbitals of two chlorine atom. So, less amount of energy is required to break the bond of $F_2$ in comparison to $ Cl_2$.
P block elements are those in which the last electron enters any of the three p-orbitals of their respective shells. Since a p-subshell has three degenerate p-orbitals each of which can accommodate two electrons, therefore in all there are six groups of p-block elements.
P block elements are shiny and usually a good conductor of electricity and heat as they have a tendency to lose an electron. You will find some amazing properties of elements in a P-block element like gallium. It’s a metal that can melt in the palm of your hand. Silicon is also one of the most important metalloids of the p-block group as it is an important component of glass.