Step 1: Understanding self-inductance of a solenoid.
The self-inductance \( L \) of a solenoid is given by the formula: \[ L = \frac{\mu_0 \mu_r n^2 A l}{l} \] where: - \( \mu_0 \) is the permeability of free space, - \( \mu_r \) is the relative permeability of the medium, - \( n \) is the number of turns per unit length, - \( A \) is the cross-sectional area, and - \( l \) is the length of the solenoid. From this formula, we see that \( L \) depends on the cross-sectional area \( A \) and the relative permeability \( \mu_r \), but does not depend on the geometry of the solenoid beyond the area. Additionally, the inductance is independent of the length \( l \) since it cancels out in the formula.
Step 2: Analyzing the options.
(A) It depends on the geometry of solenoid: Correct — The inductance depends on the cross-sectional area \( A \), and so on the geometry.
(B) It does not depend on geometry of solenoid: Incorrect — It depends on the cross-sectional area \( A \).
(C) It depends on cross-sectional area of solenoid: Correct — The inductance depends on the cross-sectional area \( A \) of the solenoid.
(D) It depends on relative permeability of the medium: Correct — The inductance depends on the relative permeability \( \mu_r \) of the medium inside the solenoid.
Step 3: Conclusion.
The correct answers are (A), (C) and (D).

Identify the taxa that constitute a paraphyletic group in the given phylogenetic tree.
The vector, shown in the figure, has promoter and RBS sequences in the 300 bp region between the restriction sites for enzymes X and Y. There are no other sites for X and Y in the vector. The promoter is directed towards the Y site. The insert containing only an ORF provides 3 fragments after digestion with both enzymes X and Y. The ORF is cloned in the correct orientation in the vector using the single restriction enzyme Y. The size of the largest fragment of the recombinant plasmid expressing the ORF upon digestion with enzyme X is ........... bp. (answer in integer) 