Question:

Which of the following statements, about the advantage of roasting of sulphide ore before reduction is not true?

Updated On: Sep 3, 2024
  • The $\Delta G^{\circ}_f$ of the sulphide is greater than those for $CS_2$ and $H_2S$.
  • The $\Delta G_f^{\circ}$ is negative for roasting of sulphide ore to oxide.
  • Roasting of the sulphide to the oxide is thermodynamically feasible.
  • Carbon and hydrogen are suitable reducing agents for metal sulphides.
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The Correct Option is D

Solution and Explanation

The sulphide ore is roasted to oxide before reduction because the $\Delta G_f^{\circ}$ of most of the sulphides are greater than those of $CS_2$ and $H_2S$, therefore neither C nor H can reduce metal sulphide to metal. Further, the standard free energies of formation of oxide are much less than those of $SO_2$. Hence oxidation of metal sulphides to metal oxide is thermodynamically favourable.
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Concepts Used:

General Principles and Processes of Isolation of Elements

What are Ores and Minerals? 

Minerals are the naturally occurring, homogeneous inorganic solid substances. They are having a definite chemical composition and crystalline structure, hardness and color. For example, copper pyrite, calamine, etc.

Impurities in an ore are called gauge. The removal of a gauge from the ore is called concentration ore. 

Several steps are involved in the extraction of pure metal from ores. Major steps are as follows –

  • Concentration of the ore
  • Isolation of the metal from its concentrated ore
  • Purification of the metal