Question

Which of the following sets are correctly matched?

Molecule	Hybridization	Geometry
I. BrF5	sp3d2	square pyramidal
II. XeF6	sp3d3	Distorted octahedral
III. SF4	dsp2	square planar
IV. PbCl2	sp	linear

• A. I & IV
• B. II & III
• C. III & IV
• D. I & II

Hint:

Always consider both bonding and lone pairs when predicting geometry and hybridization.

Answer 1

The Correct Option is D

Step 1: Analyze each molecule's geometry and hybridization
I. BrF\textsubscript{5}: Br has 7 valence electrons; forms 5 bonds and 1 lone pair square pyramidal Hybridization: sp\textsuperscript{3}d\textsuperscript{2} ✓ II. XeF\textsubscript{6}: Xe has 8 valence electrons; forms 6 bonds and 1 lone pair distorted octahedral Hybridization: sp\textsuperscript{3}d\textsuperscript{3} ✓ III. SF\textsubscript{4}: S has 6 valence electrons; forms 4 bonds and 1 lone pair seesaw geometry, not square planar ✗ Hybridization: sp\textsuperscript{3}d ✗ IV. PbCl\textsubscript{2}: With lone pairs on Pb, actual shape is bent, not linear ✗ Hybridization: sp\textsuperscript{3} ✗ Step 2: Final matching sets
Only I and II are correctly matched. \[ \boxed{\text{Correctly matched: I and II}} \]