Oxidizing agents readily accept electrons and get reduced. Let's consider the common oxidation states of the given lanthanides:
La and Lu: These lanthanides predominantly exist in the +3 oxidation state and are not strong oxidizing agents.
Eu and Yb: These lanthanides exhibit +2 and +3 oxidation states. Eu2+ and Yb2+ are reducing agents (they tend to lose electrons and get oxidized).
Therefore, only Ce4+ and Tb4+ from the given options are good oxidizing agents.
Given below are two statements:
Statement (I): The first ionization energy of Pb is greater than that of Sn.
Statement (II): The first ionization energy of Ge is greater than that of Si.
In light of the above statements, choose the correct answer from the options given below:
The product (A) formed in the following reaction sequence is:

\[ \begin{array}{|c|c|} \hline \textbf{LIST-I (Redox Reaction)} & \textbf{LIST-II (Type of Redox Reaction)} \\ \hline A. \, CH_4(g) + 2O_2(g) \rightarrow CO_2(g) + 2H_2O(l) & I. \, \text{Disproportionation reaction} \\ B. \, 2NaH(s) \rightarrow 2Na(s) + H_2(g) & II. \, \text{Combination reaction} \\ C. \, V_2O_5(s) + 5Ca(s) \rightarrow 2V(s) + 5CaO(s) & III. \, \text{Decomposition reaction} \\ D. \, 2H_2O(aq) \rightarrow 2H_2(g) + O_2(g) & IV. \, \text{Displacement reaction} \\ \hline \end{array} \]
