Oxidizing agents readily accept electrons and get reduced. Let's consider the common oxidation states of the given lanthanides:
La and Lu: These lanthanides predominantly exist in the +3 oxidation state and are not strong oxidizing agents.
Eu and Yb: These lanthanides exhibit +2 and +3 oxidation states. Eu2+ and Yb2+ are reducing agents (they tend to lose electrons and get oxidized).
Therefore, only Ce4+ and Tb4+ from the given options are good oxidizing agents.
Given below are two statements:
Statement (I): The first ionization energy of Pb is greater than that of Sn.
Statement (II): The first ionization energy of Ge is greater than that of Si.
In light of the above statements, choose the correct answer from the options given below:
List-I | List-II | ||
(A) | 1 mol of H2O to O2 | (I) | 3F |
(B) | 1 mol of MnO-4 to Mn2+ | (II) | 2F |
(C) | 1.5 mol of Ca from molten CaCl2 | (III) | 1F |
(D) | 1 mol of FeO to Fe2O3 | (IV) | 5F |