Question:

Which of the following is the correct order of stability for the given superoxides?

Updated On: Jun 21, 2024
  • \(\text{KO}_2 < \text{RbO}_2 < \text{CsO}_2\)
  • \(\text{CsO}_2 < \text{RbO}_2 < \text{KO}_2\)
  • \(\text{RbO}_2 < \text{CsO}_2 < \text{KO}_2\)
  • \(\text{KO}_2 < \text{CsO}_2 < \text{RbO}_2\)
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The Correct Option is A

Solution and Explanation

The correct option is (A): \(\text{KO}_2 < \text{RbO}_2 < \text{CsO}_2\)
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