Step 1: Solubility rule.
Polar compounds with hydrogen bonding are highly soluble in water. Non-polar compounds are insoluble.
Step 2: Analyze options.
(A) CH$_3$OH: Polar, forms H-bonds → soluble.
(B) CHCl$_3$: Weak polarity, limited solubility.
(C) CCl$_4$: Non-polar, insoluble.
(D) CS$_2$: Non-polar, insoluble.
Step 3: Conclusion.
The correct answer is (A) CH$_3$OH.