Question:

Which of the following is an outer orbital complex?

Updated On: Jun 14, 2022
  • $ [Fe(CN)_6]^{4-} $
  • $ [FeF_6]^{3-} $
  • $ [Co(NH_3)_6]^{3+} $
  • $ [Co(CN)_6]^{3-} $
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The Correct Option is B

Solution and Explanation

In $[FeF_6]^{4-}$ and $[Fe(CN)_6]^{4-}$, iron is in $+2$ oxidation state.


$F^-$ is a weak ligand, hence $3d$ electrons do not pair up. As a result, $[FeF_6]^{4-}$ has four unpaired electrons and it forms outer orbital complex ($sp ^3d^2$-hybridisation). Whereas, $CN^-$ is a strong ligand, hence $3d$ electrons
pair up. As a result, there is no unpaired electrons and it form inner orbital complex ($d^2sp^3$ hybridisation).
In $[CoCNH_3)_6]^{3+}$ and $[Co(CN)_6]^{3-}$, cobalt is in $+3$ oxidation state.


$NH_3$ and $CN^-$, both are strong held ligand, hence $3d$ electrons pair up and both form inner orbital complex ($d^2sp^3$ hybridisation).
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Concepts Used:

Coordination Compounds

A coordination compound holds a central metal atom or ion surrounded by various oppositely charged ions or neutral molecules. These molecules or ions are re-bonded to the metal atom or ion by a coordinate bond.

Coordination entity:

A coordination entity composes of a central metal atom or ion bonded to a fixed number of ions or molecules.

Ligands:

A molecule, ion, or group which is bonded to the metal atom or ion in a complex or coordination compound by a coordinate bond is commonly called a ligand. It may be either neutral, positively, or negatively charged.