Question:

Which of the following fluoride preparation combines with hydroxyapatite crystals to form calcium fluoride, which further diffuses to form fluorapatite crystals?

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Sodium fluoride is effective in promoting the formation of fluorapatite, which strengthens tooth enamel and improves its resistance to decay.
Updated On: Apr 23, 2025
  • Stannous fluoride
  • Sodium fluoride
  • Amine fluoride
  • APF
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The Correct Option is B

Solution and Explanation

Sodium fluoride (NaF) is a fluoride preparation that interacts with hydroxyapatite crystals in the tooth structure to form calcium fluoride (CaF). This calcium fluoride further diffuses into the enamel, eventually forming fluorapatite crystals, which are more resistant to acid dissolution and provide enhanced protection against tooth decay.
Other fluoride preparations like stannous fluoride and amine fluoride do not interact with hydroxyapatite in the same way to form fluorapatite. Acidulated phosphate fluoride (APF) also does not primarily rely on this mechanism for fluoride incorporation.
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