Which of the following expressions correctly represents the equivalent conductance at infinite dilution of ${Al2(SO4)3}$ ? Given that ${\wedge^{\circ}_{Al^{3+}}}$ and ${- \wedge^{\circ}_{SO^{2-}_4}}$ are the equivalent conductances at infinite dilution of the respective ions
- ${ \wedge^{\circ}_{Al^{3+}} + \wedge^{\circ}_{SO_4^{2-}}}$
- $ \left({\wedge^{\circ}_{Al^{3+}} + \wedge^{\circ}_{SO_4^{2-}}} \right) \times 6$
- $ \frac{1}{3}{\wedge^{\circ}_{Al^{3+}} + \frac{1}{2} \wedge^{\circ}_{SO_4^{2-}}} $
- ${2 \wedge^{\circ}_{Al^{3+}} + 3 \wedge^{\circ}_{SO_4^{2-}}}$
The Correct Option is A
Approach Solution - 1
Since equivalent conductance's are given only for ions, the equivalent conductance at infinite dilution,
$\Lambda _{eq}^{\infty }=\Lambda _{Al\,3+}^{o}+\Lambda _{so_{4}^{2-}}^{o}$
Approach Solution -2
Ans: The equivalent conduction at the infinite dilution (Λ°), for an electrolyte is calculated by the use of Kohlrausch’s law. It states that,
At infinite dilution, each of the ion makes a constant contribution towards the equivalent conductivity of an electrolyte, this is irrespective of the nature of the other ion that is present in the solution.
the expression for the equivalent conductance at infinite dilution of Al2(SO4)3 is:
Λ°(Al2(SO4)3) = 2Λ°(Al^3+) + 3Λ°(SO4^2-)
Since equivalent conductance's are given only for ions, the equivalent conductance at infinite dilution,
Λ°(Al^3+) + Λ°(SO4^2-)
Top Questions on Electrochemistry
If the molar conductivity ($\Lambda_m$) of a 0.050 mol $L^{–1}$ solution of a monobasic weak acid is 90 S $cm^{2} mol^{–1}$, its extent (degree) of dissociation will be:
[Assume: $\Lambda^0$ = 349.6 S $cm^{2} mol^{–1}$ and $\Lambda^0_{\text{acid}}$ = 50.4 S$ cm^{2} mol^{–1}$]- NEET (UG) - 2025
- Chemistry
- Electrochemistry
- Assertion (A): Cu cannot liberate \( H_2 \) on reaction with dilute mineral acids. Reason (R): Cu has positive electrode potential.
- CBSE CLASS XII - 2025
- Chemistry
- Electrochemistry
- The charge required for the reduction of 1 mol of \( MnO_4^- \) to \( MnO_2 \) is
- CBSE CLASS XII - 2025
- Chemistry
- Electrochemistry
- Account for the following:
Conductivity of CH\(_3\)COOH decreases on dilution.- CBSE CLASS XII - 2025
- Chemistry
- Electrochemistry
- Account for the following:
On the basis of \( E^\circ \) values, O\(_2\) gas should be liberated at anode but it is Cl\(_2\) gas which is liberated in the electrolysis of aqueous NaCl.- CBSE CLASS XII - 2025
- Chemistry
- Electrochemistry
Questions Asked in NEET exam
- With the help of the given pedigree, find out the probability for the birth of a child having no disease and being a carrier (has the disease mutation in one allele of the gene) in the F3 generation.
- NEET (UG) - 2025
- Genetics
A sphere of radius R is cut from a larger solid sphere of radius 2R as shown in the figure. The ratio of the moment of inertia of the smaller sphere to that of the rest part of the sphere about the Y-axis is :
- NEET (UG) - 2025
- Moment Of Inertia
- Two cities X and Y are connected by a regular bus service with a bus leaving in either direction every T min. A girl is driving scooty with a speed of 60 km/h in the direction X to Y. She notices that a bus goes past her every 30 minutes in the direction of her motion, and every 10 minutes in the opposite direction. Choose the correct option for the period T of the bus service and the speed (assumed constant) of the buses.
- NEET (UG) - 2025
- Relative Velocity
- A microscope has an objective of focal length \(f_o = 2\) cm and an eyepiece of focal length \(f_e = 4\) cm. The tube length of the microscope is \(L = 40\) cm. If the distance of distinct vision of eye is \(D = 25\) cm, the magnification in the microscope is:
- NEET (UG) - 2025
- Optical Instruments
A bob of heavy mass \(m\) is suspended by a light string of length \(l\). The bob is given a horizontal velocity \(v_0\) as shown in figure. If the string gets slack at some point P making an angle \( \theta \) from the horizontal, the ratio of the speed \(v\) of the bob at point P to its initial speed \(v_0\) is :
- NEET (UG) - 2025
- Pendulums
Concepts Used:
Electrochemical Cells
An electrochemical cell is a device that is used to create electrical energy through the chemical reactions which are involved in it. The electrical energy supplied to electrochemical cells is used to smooth the chemical reactions. In the electrochemical cell, the involved devices have the ability to convert the chemical energy to electrical energy or vice-versa.
Classification of Electrochemical Cell:
Cathode
- Denoted by a positive sign since electrons are consumed here
- A reduction reaction occurs in the cathode of an electrochemical cell
- Electrons move into the cathode
Anode
- Denoted by a negative sign since electrons are liberated here
- An oxidation reaction occurs here
- Electrons move out of the anode
Types of Electrochemical Cells:
Galvanic cells (also known as Voltaic cells)
- Chemical energy is transformed into electrical energy.
- The redox reactions are spontaneous in nature.
- The anode is negatively charged and the cathode is positively charged.
- The electrons originate from the species that undergo oxidation.
Electrolytic cells
- Electrical energy is transformed into chemical energy.
- The redox reactions are non-spontaneous.
- These cells are positively charged anode and negatively charged cathode.
- Electrons originate from an external source.