As explained in the previous response, the Hell-Volhard-Zelinsky (HVZ) reaction is specific to carboxylic acids that have α-hydrogen atoms.
Let's reiterate the analysis:
- Option 1: R-CH2-COOH: This is a carboxylic acid with α-hydrogen atoms (the hydrogens on the CH2 group). Therefore, it will undergo the HVZ reaction.
- Option 2: R3C-CHO: This is an aldehyde, not a carboxylic acid. The HVZ reaction does not apply to aldehydes.
- Option 3: R2CO: This is a ketone, not a carboxylic acid. The HVZ reaction does not apply to ketones.
- Option 4: H-COOH: This is formic acid. While it is a carboxylic acid, it lacks α-hydrogen atoms. Therefore, it will not undergo the HVZ reaction.
Therefore, the compound that will give the Hell-Volhard-Zelinsky reaction is R-CH2-COOH.
The correct answer is:
Option 1: R-CH2-COOH