Question:

Which of the following compounds will give the Hell-Volhard-Zelinsky reaction?

Updated On: May 15, 2025
  • R-CH$_2$-COOH
  • R$_3$C-CHO
  • R$_2$CO
  • H-COOH
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The Correct Option is A

Approach Solution - 1

The Hell-Volhard-Zelinsky reaction is a halogenation reaction specific to carboxylic acids with at least one α-hydrogen atom. This reaction requires the presence of α-hydrogen adjacent to the carboxylic acid group (-COOH) for the halogenation process to occur.

Let's analyze each option: 

  • R-CH2-COOH: This compound is a carboxylic acid and has an α-hydrogen (the hydrogen attached to the carbon adjacent to the carbonyl carbon). Therefore, it can undergo the Hell-Volhard-Zelinsky reaction.
  • R3C-CHO: This is an aldehyde and not a carboxylic acid. It lacks the α-hydrogen that is adjacent to a carboxylic acid group, making it unsuitable for this reaction.
  • R2CO: This is a ketone, which similarly does not contain the necessary α-hydrogen next to a carboxylic acid functionality.
  • H-COOH: Formic acid does not have any α-hydrogen atom adjacent to its carboxyl group; hence, it cannot participate in the Hell-Volhard-Zelinsky reaction.

Therefore, the correct answer is R-CH2-COOH as it fulfills the criteria necessary for the Hell-Volhard-Zelinsky reaction.

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Approach Solution -2

As explained in the previous response, the Hell-Volhard-Zelinsky (HVZ) reaction is specific to carboxylic acids that have α-hydrogen atoms.

Let's reiterate the analysis:

  • Option 1: R-CH2-COOH: This is a carboxylic acid with α-hydrogen atoms (the hydrogens on the CH2 group). Therefore, it will undergo the HVZ reaction.
  • Option 2: R3C-CHO: This is an aldehyde, not a carboxylic acid. The HVZ reaction does not apply to aldehydes.
  • Option 3: R2CO: This is a ketone, not a carboxylic acid. The HVZ reaction does not apply to ketones.
  • Option 4: H-COOH: This is formic acid. While it is a carboxylic acid, it lacks α-hydrogen atoms. Therefore, it will not undergo the HVZ reaction.

Therefore, the compound that will give the Hell-Volhard-Zelinsky reaction is R-CH2-COOH.

The correct answer is option A: R-CH2-COOH

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