To determine the most powerful reducing agent in aqueous solution among the given metals, we need to consider their standard reduction potentials. A reducing agent donates electrons to another substance and gets oxidized in the process. The strength of a reducing agent is inversely related to its standard electrode potential, meaning that the metal with the lowest (most negative) standard reduction potential will be the most powerful reducing agent.
| Metal | Standard Reduction Potential (V) |
|---|---|
| Potassium (K) | -2.93 |
| Sodium (Na) | -2.71 |
| Barium (Ba) | -2.90 |
| Lithium (Li) | -3.04 |
While based on standard electrode potentials, Lithium seems like it could be a candidate due to its highly negative potential, in practice, when considering their behavior in aqueous solutions and their reactivity, the metallic nature and solvation effects make potassium the most effective reducing agent among these choices.
Thus, in an aqueous solution, Potassium (K) acts as the most powerful reducing agent based on these considerations.
A substance 'X' (1.5 g) dissolved in 150 g of a solvent 'Y' (molar mass = 300 g mol$^{-1}$) led to an elevation of the boiling point by 0.5 K. The relative lowering in the vapour pressure of the solvent 'Y' is $____________ \(\times 10^{-2}\). (nearest integer)
[Given : $K_{b}$ of the solvent = 5.0 K kg mol$^{-1}$]
Assume the solution to be dilute and no association or dissociation of X takes place in solution.