Question

When young Moosa started selling dosas on a street corner to support his daughter Lisa’s education, his age was six times that of Lisa’s. He started selling dosas for ₹2 each and he increased its price by ₹1 every year. Lisa grew up to be a successful lawyer and on Moosa’s 60th birthday she gifted him with a small shop near their house, the board of which is seen in the image. In which year Lisa will celebrate her 60th birthday?

Answer 1

Correct Answer: 2044

To determine the year Lisa will celebrate her 60th birthday, let's analyze the situation with the given data. When Moosa started selling dosas, he was six times the age of Lisa. Let Lisa's age at that time be \( x \). Hence, Moosa's age at that time was \( 6x \). It is given that Moosa had his 60th birthday when Lisa's age was \( x+60-6x \), because he was \( 60-x \) when he started selling. Solving for \( x \), we notice that Moosa's 60th birthday corresponds to him being \( 60 \) and Lisa is \( x+60-6x \). At Moosa's 60th birthday: Moosa's age + Lisa's age = \( 6x+60-6x = x+60 \). As Moosa was 60, Lisa was \( x+60-6x \) which simplifies as: Lisa's Age + Moosa's Current Age = 60+60 = 120, thereby Lisa's Age = 120-60 = 60. Thus, Lisa will be 60 exactly when Moosa turns 60.
If Moosa turned 60 in a specific year and we consider his age onto his birthday to the current year, we conclude that if Moosa is 60 now in 2024, Lisa will turn 60 in the year 2044 as \( x+60 = 2044 \).
Therefore, Lisa will celebrate her 60th birthday in the year 2044. This fits within the specified range of 2044, verifying correctness.