Step 1: Identify initial complex of Fe\(^{3+}\) in water.
Fe\(^{3+}\) in aqueous medium exists mainly as:
\[
[Fe(H_2O)_6]^{3+}
\]
Step 2: Addition of thiocyanate ion.
SCN\(^{-}\) replaces one water molecule and forms a red coloured complex.
\[
[Fe(H_2O)_6]^{3+} + SCN^- \rightarrow [Fe(H_2O)_5(SCN)]^{2+} + H_2O
\]
Step 3: Charge calculation.
Fe\(^{3+}\) + 5 neutral water + SCN\(^{-}\) gives overall charge:
\[
+3 + 0 -1 = +2
\]
Step 4: Final conclusion.
The complex formed is \([Fe(H_2O)_5(SCN)]^{2+}\).
Final Answer:
\[
\boxed{[Fe(H_2O)_5(SCN)]^{2+}}
\]