Question:

When ethyl alcohol is heated with conc. H\(_2\)SO\(_4\), product obtained is

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Ethanol + conc. H\(_2\)SO\(_4\) on heating gives ethene by dehydration.
Updated On: Jan 3, 2026
  • CH\(_3\)COOC\(_2\)H\(_5\)
  • C\(_2\)H\(_2\)
  • C\(_2\)H\(_6\)
  • C\(_2\)H\(_4\)
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The Correct Option is D

Solution and Explanation

Step 1: Reaction of ethanol with conc. H\(_2\)SO\(_4\).
Concentrated sulphuric acid acts as a dehydrating agent.
Step 2: Dehydration of ethanol.
On heating ethanol at about \(443K\), it loses water and forms ethene.
\[ CH_3CH_2OH \xrightarrow{conc.\,H_2SO_4,\,443K} CH_2=CH_2 + H_2O \]
Step 3: Identify product.
The product is ethene \(C_2H_4\).
Final Answer:
\[ \boxed{C_2H_4} \]
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