Question:
When ammonia is heated with cupric oxide, a molecule of ammomia will
When ammonia is heated with cupric oxide, a molecule of ammomia will
Updated On: Jul 12, 2022
- Gain 3 electrons
- Lose 3 electrons
- Gain 2 electrons
- Lose 2 electrons
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The Correct Option is B
Solution and Explanation
$ {2NH_3 + 3CuO -> N2 + H20 + 3Cu }$
$ {2NH3 -> N_2}$
(O.S. = -3) (O.S. = 0)
Thus each N atom (or each $NH_3$ molecule) loses 3 electrons.
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Concepts Used:
P-Block Elements
- P block elements are those in which the last electron enters any of the three p-orbitals of their respective shells. Since a p-subshell has three degenerate p-orbitals each of which can accommodate two electrons, therefore in all there are six groups of p-block elements.
- P block elements are shiny and usually a good conductor of electricity and heat as they have a tendency to lose an electron. You will find some amazing properties of elements in a P-block element like gallium. It’s a metal that can melt in the palm of your hand. Silicon is also one of the most important metalloids of the p-block group as it is an important component of glass.
P block elements consist of:
- Group 13 Elements: Boron family
- Group 14 Elements: Carbon family
- Group 15 Elements: Nitrogen family
- Group 16 Elements: Oxygen family
- Group 17 Elements: Fluorine family
- Group 18 Elements: Neon family