Question:
When a uranium isotope $^{235}_92 U$ is bombarded with a neutron, it generates $^{89}_{36} Kr$, three neutrons and :
When a uranium isotope $^{235}_92 U$ is bombarded with a neutron, it generates $^{89}_{36} Kr$, three neutrons and :
Updated On: Apr 14, 2025
- $^{144}_{56} Ba$
- $^{91}_{40} Zr$
- $^{101}_{36} Kr$
- $^{103}_{36} Kr$
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The Correct Option is A
Solution and Explanation
$^{235}_{92}U + ^{1}_{0}n \rightarrow ^{89}_{36}Kr+3 ^{1}_{0}n+X_{X}^{A}$
$92+0=36+Z$
$\Rightarrow Z=56$
$235+1=89+3+A$
$\Rightarrow A=144$
So, $^{144}_{56}Ba$ is generated
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