Question:
When a metal wire elongates by hanging a load $Mg$ on it, the gravitational potential energy of mass $M$ decreases by $ Mgl $ . This energy appears
When a metal wire elongates by hanging a load $Mg$ on it, the gravitational potential energy of mass $M$ decreases by $ Mgl $ . This energy appears
Updated On: Sep 8, 2023
- as elastic potential energy completely
- as thermal energy completely
- half as elastic potential energy and half as thermal energy
- as kinetic energy of the load completely
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The Correct Option is C
Solution and Explanation
When a metal wire elongates by hanging a load $ Mg $ on it, decrease in potential energy of the load $ =Mgl $
(where $ l= $ elongation in metal wire) Elastic potential energy stored in stretched wire
$ =\frac{1}{2}\times Mgl $ Difference of $ Mgl $ and $ \frac{1}{2}Mgl $
appears as heat energy in the stretched wire.
$ \therefore $ Energy appearing as heat
$ =Mgl-\frac{1}{2}Mgl $ $ =\frac{1}{2}Mgl $
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Concepts Used:
Gravitation
In mechanics, the universal force of attraction acting between all matter is known as Gravity, also called gravitation, . It is the weakest known force in nature.
Newton’s Law of Gravitation
According to Newton’s law of gravitation, “Every particle in the universe attracts every other particle with a force whose magnitude is,
- F ∝ (M1M2) . . . . (1)
- (F ∝ 1/r2) . . . . (2)
On combining equations (1) and (2) we get,
F ∝ M1M2/r2
F = G × [M1M2]/r2 . . . . (7)
Or, f(r) = GM1M2/r2
The dimension formula of G is [M-1L3T-2].