Question:

When a lens of refractive index $\mu_1$ is placed in a liquid of refractive index $\mu_2$, the lens looks to be disappeared only if

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A lens becomes optically invisible when its refractive index matches that of the surrounding medium.
Updated On: Feb 4, 2026
  • $2\mu_1 = \mu_2$
  • $\mu_1 = \dfrac{2\mu_2}{3}$
  • $\mu_1 = \mu_2$
  • $\mu_1 = \dfrac{3\mu_2}{2}$
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The Correct Option is C

Solution and Explanation

Step 1: Understand condition for lens visibility.
A lens produces refraction only when there is a difference between refractive indices of the lens and the surrounding medium.
Step 2: Case when lens disappears.
If refractive index of the lens equals that of the surrounding liquid, there is no refraction at the boundary.
Step 3: Final conclusion.
When $\mu_1 = \mu_2$, the lens does not bend light and hence appears invisible.
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