When a = 0, b = – 1, find the value of the given expressions: (i) 2a+2b (ii) 2a2+b2+1 (iii) 2a2b+2ab2+ab (iv) a2+ab+2
Solution and Explanation
(i) 2a+2b = 2(0)+2(-1) = 0-2=-2 [putting a=0,b=-1]
(ii) 2a2+b2+1 = 2(0)2+(-1)2+1 = 2×0+1+1 = 0+2 = 2 [putting a=0,b=-1]
(iii) 2a2b+2ab2+ab = 2(0)2(-1)+2(0)(-1)2+(0)(-1) = 0+0+0 = 0 [putting a=0,b=-1]
(iv) a2+ab+2 = (0)2+(0)(-1)+2 = 2 [putting a = 0,b=-1]
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