Question:

When $1$ mol $CrCl_{3}\cdot 6H_{2}O$ is treated with excess of $AgNO_{3}$, $3$ mol of $AgCl$ are obtained. The formula of the complex is

Updated On: Jul 7, 2022
  • $[CrCl_{3}(H_{2}O )_{3}] \cdot 3H_{2}O$
  • $[CrCl_{2}(H_{2}O)_{4}]Cl\cdot 2H_{2}O$
  • $[CrCl(H_{2}O )_{5}]Cl_{2}\cdot H_{2}O$
  • $[Cr(H_{2}O )_{6}]Cl_{3}$
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The Correct Option is D

Solution and Explanation

As $3$ moles of $AgCl$ are obtained when $1$ mol of $CrCl_{3}\cdot 6H_{2}O$ is treated with excess of $AgNO_{3}$ which shows that one molecule of the complex gives three chloride ions in solution. Hence, formula of the complex is $[Cr(H_{2}O)_{6}]Cl_{3}.$
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Notes on coordination compounds

Concepts Used:

Coordination Compounds

A coordination compound holds a central metal atom or ion surrounded by various oppositely charged ions or neutral molecules. These molecules or ions are re-bonded to the metal atom or ion by a coordinate bond.

Coordination entity:

A coordination entity composes of a central metal atom or ion bonded to a fixed number of ions or molecules.

Ligands:

A molecule, ion, or group which is bonded to the metal atom or ion in a complex or coordination compound by a coordinate bond is commonly called a ligand. It may be either neutral, positively, or negatively charged.