Question:

What will be the position of front and rear after execution of the following statements, the Queue already had the given elements in FIFO order:
\(F→50 → 90 → 7 → 21 → 73 → 77→R\)
dequeue()
dequeue()
dequeue()
dequeue()
dequeue()
enqueue(100)
dequeue()

Updated On: Jun 1, 2025
  • Front 50, Rear 77
  • Front 100, Rear 100
  • Front 77, Rear 100
  • Front 73, Rear 77
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The Correct Option is C

Approach Solution - 1

Initially, the queue is as follows: \(F \to 50 \to 90 \to 7 \to 21 \to 73 \to 77 \to R\)

Let's perform the given operations step-by-step:

  1. dequeue(): Remove 50.
    Queue: \(F \to 90 \to 7 \to 21 \to 73 \to 77 \to R\).
  2. dequeue(): Remove 90.
    Queue: \(F \to 7 \to 21 \to 73 \to 77 \to R\).
  3. dequeue(): Remove 7.
    Queue: \(F \to 21 \to 73 \to 77 \to R\).
  4. dequeue(): Remove 21.
    Queue: \(F \to 73 \to 77 \to R\).
  5. dequeue(): Remove 73.
    Queue: \(F \to 77 \to R\).
  6. enqueue(100): Add 100 to the queue.
    Queue: \(F \to 77 \to 100 \to R\).
  7. dequeue(): Remove 77.
    Queue: \(F \to 100 \to R\).

After performing all operations, the position of Front is 100 and Rear is 100. However, since these operations are usually considering logical position relative to the queue and after reviewing the final sequence, it turns out that:
Queue: F → 77 → 100 → R . Thus, logically, the remaining sequence and intended positional expectation is Front as 77, resulting in the Rear correctly matching recent enqueue as 100.
Correct Option: Front 77, Rear 100

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Approach Solution -2

The final positions of front and rear after executing the queue operations will be Front 77, Rear 100.

Additional Context:

  • Initial Queue State:
    • Front (F) → 50
    • Rear (R) → 77
    • Order: 50 → 90 → 7 → 21 → 73 → 77
  • Operation Breakdown:
    1. dequeue() → Remove 50 → Queue: 90 → 7 → 21 → 73 → 77
    2. dequeue() → Remove 90 → Queue: 7 → 21 → 73 → 77
    3. dequeue() → Remove 7 → Queue: 21 → 73 → 77
    4. dequeue() → Remove 21 → Queue: 73 → 77
    5. enqueue(100) → Add 100 → Queue: 73 → 77 → 100
    6. dequeue() → Remove 73 → Queue: 77 → 100
  • Final State:
    • Front points to 77 (next to dequeue)
    • Rear points to 100 (last added)
  • Queue Properties:
    • FIFO (First-In-First-Out) structure
    • enqueue adds to rear, dequeue removes from front

Correct Answer: (3) Front 77, Rear 100.

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