We have
\(⇒ \frac{(M + S)}{2 }= 140\)
\(⇒ S + E = 140\)
We cannot find values of his marks obtained from the above two equations and from (i) only weights of the subjects are given. To find the weighted average we need both weights and values of the subjects. So from (i) and (ii) we cannot solve the question. Hence, option D is the correct answer.