Question:

What is the weight of oxygen required for the complete combustion of 2.8 kg of ethylene?

Updated On: Jul 12, 2022
  • 2.8 kg
  • 6.4 kg
  • 9.6 kg
  • 96 kg
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The Correct Option is C

Solution and Explanation

(C) $\begin {array} \ C_2 H_4 \\ {12\times 2 + 4 \times 1} \\ =28g \end{array} + \begin {array} \ \ \ 3O_2 \\ {16\times 6} \\ =96g \end{array} \rightarrow 2CO_2 + 2H_2O $ \therefore For the combustion of 28×10328 \times 10^{-3} kg of ethylene oxygen required =96×103 kg= 96 \times 10^{-3} \ kg \therefore For the combustion of 2.8 kg of ethylene oxygen required 96×103×2.828×103=9.6kg \frac {96 \times 10^{-3} \times 2.8}{28 \times 10^{-3}} = 9.6 kg
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Top Questions on Organic Chemistry- Some Basic Principles and Techniques

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Concepts Used:

Organic Chemistry – Some Basic Principles and Techniques - Reaction Mechanism

SN1 Reaction Mechanism:

SN1 reaction mechanism takes place by following three steps –

  • Formation of carbocation 
  • Attack of nucleophile 
  • Deprotonation 

SN2 Reaction Mechanism:

The SN2 reaction mechanism involves the nucleophilic substitution reaction of the leaving group (which generally consists of halide groups or other electron-withdrawing groups) with a nucleophile in a given organic compound.

Electrophilic Aromatic Substitution Reaction Mechanism:

The mechanism of an electrophilic aromatic substitution reaction contains three main components which are:

  1. A new sigma bond from C=C is formed during the reaction in the arene nucleophile.
  2. Due to the breaking of the C-H sigma bond, a proton is removed.
  3. The C=C bond is reformed and it restores the aromaticity of the compound.

Electrophilic Substitution Reaction Mechanism:

The electrophilic substitution reaction mechanism is composed of three steps, which will be discussed more below.

  • Electrophile Generation
  • Carbocation Formation
  • Proton Removal