In a balanced binary search tree (e.g., AVL or Red-Black tree): - The height is $O(\log n)$ due to balancing properties. - Insertion involves traversing from root to leaf to find the insertion point, which takes $O(\log n)$. - After insertion, rebalancing (rotations) takes $O(\log n)$ in worst case. Thus, total time complexity is $O(\log n)$. Option (1) is correct.