Question

What is the overall order of the reaction which has the following rate expression? Rate = k[A]$^\frac{1}{2}$[B]$^\frac{3}{2}$

• A. One
• B. Two
• C. Zero
• D. Three

Answer 1

The Correct Option is D

The overall order of a reaction is determined by summing the exponents of the concentration terms in the rate expression. Given the rate expression: Rate = k[A]$^\frac{1}{2}$[B]$^\frac{3}{2}$, we identify the exponents for each concentration: 

The exponent of [A] is $\frac{1}{2}$.

The exponent of [B] is $\frac{3}{2}$.

To find the overall order, add these exponents:

Overall order = $\frac{1}{2}$ + $\frac{3}{2}$ = 2

Answer 2

The rate expression for a given reaction is:
Rate = k[A]^1/2[B]^3/2

The order of the reaction with respect to A is 1/2, and with respect to B is 3/2.

The overall order of the reaction is obtained by summing the exponents of the concentration terms in the rate expression. Thus, the overall order is:
\( \frac{1}{2} + \frac{3}{2} = 2 \).

Therefore, the overall order of the reaction is 2, which indicates the reaction is second-order overall.