Question:

What is the magnetic moment of $ Fe^{3+} $ ion in $ [Fe(CN)_6]^{3-} $ ?

Updated On: Jun 14, 2022
  • $ 1.73\,BM $
  • $ 5.9\,BM $
  • $Diamagnetic$
  • None of these
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The Correct Option is A

Solution and Explanation

$Fe^{3+}=[Ar] 3d^{5}$
$(\because CN^{-}$ being a strong field ligand causes pairing)
$\therefore$ Magnetic moment, $\mu = \sqrt{n(n+2)} BM$
(where, $n$ = number of unpaired electrons)
$=\sqrt{1 (1+2)} =\sqrt{3}$
$=1.73\,BM$
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Concepts Used:

Coordination Compounds

A coordination compound holds a central metal atom or ion surrounded by various oppositely charged ions or neutral molecules. These molecules or ions are re-bonded to the metal atom or ion by a coordinate bond.

Coordination entity:

A coordination entity composes of a central metal atom or ion bonded to a fixed number of ions or molecules.

Ligands:

A molecule, ion, or group which is bonded to the metal atom or ion in a complex or coordination compound by a coordinate bond is commonly called a ligand. It may be either neutral, positively, or negatively charged.