Question:

What is the drift velocity of electons, if the current flowing through a copper wire of $1\,mm$ diameter is $1.1\, A$ ? Assume that each atom of copper contributes on electron (Given, density of $Cu= 9 g \, cm^{-3}$ and atomic weight of $Cu = 63$)

Updated On: Jun 18, 2022
  • $0.3\, mm\, s^{-1}$
  • $0.5\, mm\, s^{-1}$
  • $0.1\, mm\, s^{-1}$
  • $0.2\, mm\, s^{-1}$
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The Correct Option is C

Solution and Explanation

$i=n e A v_{d}$
$n=\frac{\text { Avogadros number }}{\text { Volume of 63 gof copper }}$
$\frac{6.02 \times 10^{23}}{\frac{63 \times 10^{-3}}{9 \times 10^{3}}}=\frac{6.02 \times 10^{23}}{7} cm ^{3}$
$n=\frac{6.02 \times 10^{29}}{7} m ^{3}$
$i=n e A v_{d}$ or $v_{d}=\frac{i}{n e A}$
$=\frac{1.1 \times 7}{6.02 \times 10^{29} \times 1.6 \times 10^{-19} \times \pi \times\left(0.5 \times 10^{-3}\right)^{2}}$
$0.1 \times 10^{-3} ms ^{-1}$
$=0.1\, mm\, s ^{-1}$
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Concepts Used:

Electromagnetic Induction

Electromagnetic Induction is a current produced by the voltage production due to a changing magnetic field. This happens in one of the two conditions:-

  1. When we place the conductor in a changing magnetic field.
  2. When the conductor constantly moves in a stationary field.

Formula:

The electromagnetic induction is mathematically represented as:-

e=N × d∅.dt

Where

  • e = induced voltage
  • N = number of turns in the coil
  • Φ = Magnetic flux (This is the amount of magnetic field present on the surface)
  • t = time

Applications of Electromagnetic Induction

  1. Electromagnetic induction in AC generator
  2. Electrical Transformers
  3. Magnetic Flow Meter