Step 1: Understand the Solvay process.
The Solvay process is a method for producing sodium carbonate (soda ash, Na2CO3) from salt (NaCl), ammonia (NH3), carbon dioxide (CO2), and limestone (CaCO3). The key reactions are:
\[ \text{NH}_3 + \text{CO}_2 + \text{H}_2\text{O} \rightarrow \text{NH}_4\text{HCO}_3, \] \[ \text{NaCl} + \text{NH}_4\text{HCO}_3 \rightarrow \text{NaHCO}_3 + \text{NH}_4\text{Cl}, \] \[ 2\text{NaHCO}_3 \xrightarrow{\text{heat}} \text{Na}_2\text{CO}_3 + \text{H}_2\text{O} + \text{CO}_2. \]
The byproduct calcium chloride (CaCl2) is produced when ammonia is recovered:
\[ 2\text{NH}_4\text{Cl} + \text{Ca(OH)}_2 \rightarrow 2\text{NH}_3 + \text{CaCl}_2 + 2\text{H}_2\text{O}. \]
Step 2: Analyze the disadvantages of the Solvay process.
Salt consumption: The process requires a large amount of salt (NaCl) as a raw material. For every ton of soda ash produced, approximately 1.5 tons of salt are consumed, which is relatively high compared to alternative processes.
Co-products: The process produces calcium chloride (CaCl2) as a byproduct, which can be difficult to dispose of or sell, especially in large quantities, creating a waste management challenge.
Brine quality: The Solvay process can use low-grade brine (impure NaCl solution), which is an advantage, not a disadvantage.
Electric power: The Solvay process is not particularly energy-intensive in terms of electricity, as it relies more on chemical reactions and heat (e.g., for calcining limestone). So, “less electric power” is a disadvantage. The primary disadvantage is the higher salt consumption, increasing raw material costs and resource demand.
Step 3: Evaluate the options.
Step 4: Select the correct answer.
The disadvantage of the Solvay process is higher salt consumption, matching option (1).
The representation of octal number \((532.2){_8}\) in decimal is ____ .
Given the signal,
\(X(t) = cos t\), if \(t<0 \)
\(Sin\ t\), if \(t\ge0 \)
The correct statement among the following is?
A linear system at rest is subject to an input signal \(r(t) = 1 - e^{-t}\). The response of the system for t>0 is given by \(c(t) = 1 - e^{-2t}\). The transfer function of the system is:
In the given circuit below, voltage \(V_C(t)\) is: