In Fehling's test, when an aliphatic aldehyde is treated with Fehling's solution, a redox reaction occurs. Fehling's solution is composed of copper(II) sulfate, sodium potassium tartrate (Rochelle salt), and a strong base such as sodium hydroxide. The copper(II) ions in the solution (which give it a blue color) are reduced to copper(I) ions during the reaction.
The overall chemical reaction for an aliphatic aldehyde can be summarized as follows:
RCHO + 2Cu2+ + 5OH- → RCOO- + Cu2O + 3H2O
Here, RCHO represents the aliphatic aldehyde, and RCOO- is its oxidized form (a carboxylate ion). The critical aspect of this reaction is the formation of copper(I) oxide (Cu2O), which precipitates out as a red-brown solid. This color change from blue to red-brown confirms the presence of an aliphatic aldehyde.
Observation
Interpretation
Red-brown precipitate
Positive result for aliphatic aldehyde
The color of the copper compound formed in Fehling’s test for aliphatic aldehydes is therefore red-brown.
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In Fehling’s test for aliphatic aldehydes, a red-brown precipitate of copper(I) oxide (Cu₂O) is formed.
Fehling’s solution contains copper(II) ions (Cu²⁺), which are blue in color.
When an aldehyde is present, it reduces the copper(II) ions to copper(I) ions (Cu⁺), forming a red-brown precipitate of Cu₂O.
This red-brown color indicates the presence of an aldehyde.
Thus, the color of the copper compound formed is red-brown.
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