Question:

What is dimensional formula of thermal conductivity?

Updated On: Jun 18, 2022
  • $ [ MLT^{ - 1} \theta^{ - 1} ] $
  • $ [ MLT^{ - 3} \theta^{ - 1} ] $
  • $ [ M^2LT^{ - 3} \theta^{ - 2} ] $
  • $ [ ML^2T^{ - 2} \theta] $
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The Correct Option is B

Solution and Explanation

$ \Delta Q = KA \left( \frac{ T_1 - T_2 }{ L } \right) \Delta t $
or [ K ] = $ \frac{ [ ML^2 T^{ - 2} ] [ L ] }{ [ L^2 ] [ \theta ] [ T ] } $
$ [ MLT^{ - 3} \theta^{ - 1} ] $
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