What are X and Y respectively in the following set of reactions?
1
2
3
4
- In the first reaction, 1-butanol reacts with \(Br_2\) in the presence of red phosphorus to form 1-bromobutane by substitution of the -OH group. So, \(X =\) 1-bromobutane.
- In the second reaction, butanal is first brominated at the alpha-position by \(Br_2\)/red P, forming an alpha-bromo aldehyde intermediate. Subsequent treatment with water leads to the formation of an alpha-bromo hydroxy compound, i.e., 3-bromo-1-hydroxybutanone.
So, \(Y =\) 3-bromo-1-hydroxybutanone.
For the thermal decomposition of \( N_2O_5(g) \) at constant volume, the following table can be formed, for the reaction mentioned below: \[ 2 N_2O_5(g) \rightarrow 2 N_2O_4(g) + O_2(g) \] Given: Rate constant for the reaction is \( 4.606 \times 10^{-2} \text{ s}^{-1} \).