Question:

Weight of body at earth's surface is W. At a depth half way to the centre of earth it will be

Updated On: Jul 7, 2022
  • W/8
  • W/4
  • W/2
  • W
Hide Solution
collegedunia
Verified By Collegedunia

The Correct Option is C

Solution and Explanation

Using $g_d = g \left( 1 - \frac{d}{R}\right)$ , we get $g_d = g \left( 1 - \frac{R}{2R} \right) = \frac{g}{2}$ $(\therefore d = \frac{R}{2} given )$ Thus weight = $mg_d = \frac{mg}{2} = \frac{W}{2}$
Was this answer helpful?
0
0

Concepts Used:

Gravitation

In mechanics, the universal force of attraction acting between all matter is known as Gravity, also called gravitation, . It is the weakest known force in nature.

Newton’s Law of Gravitation

According to Newton’s law of gravitation, “Every particle in the universe attracts every other particle with a force whose magnitude is,

  • F ∝ (M1M2) . . . . (1)
  • (F ∝ 1/r2) . . . . (2)

On combining equations (1) and (2) we get,

F ∝ M1M2/r2

F = G × [M1M2]/r2 . . . . (7)

Or, f(r) = GM1M2/r2

The dimension formula of G is [M-1L3T-2].