Question:
Volume of $0.1\, M\, K _{2} Cr _{2} O _{7}$ required to oxidize $35\, mL$ of $0.5\, M\, FeSO _{4}$ solution is
Volume of $0.1\, M\, K _{2} Cr _{2} O _{7}$ required to oxidize $35\, mL$ of $0.5\, M\, FeSO _{4}$ solution is
Updated On: Jun 3, 2024
- 29.2 mL
- 17.5 mL
- 175 mL
- 145 mL
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The Correct Option is A
Solution and Explanation
$Cr _{2} O _{7}^{2-}+6 Fe ^{2+}+14 H ^{+} \rightarrow 6 Fe ^{3+}$
$+2 Cr ^{3+}+7 H _{2} O$ Hence, $1$ mol of $Cr _{2} O _{7}^{2-}=6$
mole of $Fe ^{2+}$
$\frac{M_{1} V_{1}}{1}=\frac{M_{2} V_{2}}{6}$
$V_{1}=\frac{0.1 \times V_{1}}{6 \times 0.1}$
$\frac{0.1 \times V_{1}}{1}=\frac{0.5 \times 35}{6}$
$V_{1}=29.2\, mL$
$+2 Cr ^{3+}+7 H _{2} O$ Hence, $1$ mol of $Cr _{2} O _{7}^{2-}=6$
mole of $Fe ^{2+}$
$\frac{M_{1} V_{1}}{1}=\frac{M_{2} V_{2}}{6}$
$V_{1}=\frac{0.1 \times V_{1}}{6 \times 0.1}$
$\frac{0.1 \times V_{1}}{1}=\frac{0.5 \times 35}{6}$
$V_{1}=29.2\, mL$
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Concepts Used:
Solutions
A solution is a homogeneous mixture of two or more components in which the particle size is smaller than 1 nm.
For example, salt and sugar is a good illustration of a solution. A solution can be categorized into several components.
Types of Solutions:
The solutions can be classified into three types:
- Solid Solutions - In these solutions, the solvent is in a Solid-state.
- Liquid Solutions- In these solutions, the solvent is in a Liquid state.
- Gaseous Solutions - In these solutions, the solvent is in a Gaseous state.
On the basis of the amount of solute dissolved in a solvent, solutions are divided into the following types:
- Unsaturated Solution- A solution in which more solute can be dissolved without raising the temperature of the solution is known as an unsaturated solution.
- Saturated Solution- A solution in which no solute can be dissolved after reaching a certain amount of temperature is known as an unsaturated saturated solution.
- Supersaturated Solution- A solution that contains more solute than the maximum amount at a certain temperature is known as a supersaturated solution.