Step 1: The inheritance of colour blindness follows an X-linked recessive pattern. Since the father is colour blind, his genotype must be \( X^bY \), where \( X^b \) represents the X chromosome carrying the colour blind allele. The mother is normal homozygous, so her genotype is \( X^N X^N \), where \( X^N \) represents the normal allele.
Step 2: The offspring can inherit either the \( X^b \) or \( X^N \) chromosome from the mother. The male child will inherit the \( Y \) chromosome from the father, and the \( X^N \) chromosome from the mother, resulting in a normal male child. The female child will inherit one \( X^N \) chromosome from each parent, resulting in a normal female child as well.
Thus, the vision of the children will be normal.